Faster, shorter Options

[cybernetix]

how many times you've got calculations like this:

z=Math.round((x+y)/2);

usually I use it to calculate new position for objects that shuold be on integer _x or _y, like texts or small images (to avoid blur).

so, what computer do in this case?

first operation: x+y
second operation: first_result / 2
third operation: Math.round( second_result )
fourth operation: z = third_result

and thats it.

can we do it faster ?

yes.

how?

bitwise shifting!

z=x+y>>>1;

in this case operations are:
first operation: x+y
second operation: first_result>>>1
third operation: z = second_result


one step less, 25% faster.


bitwise shifting directly change individual bits in an operand, so it is so fast that it could not be faster. also, what is important, allways returns integer, so - it is not neccessary to round() it.

in this case it is like this:

first_result >>>1 means DIVIDE first_result WITH 2¹

first_result >>>2 would means DIVIDE first_result WITH 2²

first_result >>>n would means DIVIDE first_result WITH 2n

etc

IMPORTANT: works only with positive numbers.

[cmonney]

cool 'agent'... wut about this one???:

CODE

if(true){
  do this;
}else{
  do that;
}

or

CODE

true ? do this : do that;

[cybernetix]

if you asking about speed, there is no difference, but sometimes it is more practical if you use ternary operator, thats the name of it

[*D*]

You two need a private room lol


I'm reading this, none of it makes any sense to me, but thanks Cybernetix

[cmonney]

if you asking about speed, there is no difference, but sometimes it is more practical if you use ternary operator, thats the name of it

gotcha...




+++to D+++

wut's up D... weren't you out for 3 hours???

[e.brahim]

you guys are too high for me

[MAngeles]

Original

Thanks

[Guest_esmer67_*]

thanks

[Andrew_F]

z=x+y>>>1;
never used ">>>" before...
Need to consider it more carefully//
Thanks for idea!!